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Esti aici: Qreferat » Referate mecanica

Proiect mecanisme



UNIVERSITATEA DIN PITESTI

FACULTATEA DE MECANICA

SI TEHNOLOGIE Rm VALCEA









PROIECT MECANISME






Tema Proiect:   Nr: 11


Grupa:   Nr: 8


Subgrupa:    Nr: 1


Ordine :  Nr:42













Capitolul  Nr I


Analiza structurala


Elementele mecanizmului sunt de rangul

J=3

Cuple cinematice:

--rotatie




--rotatie + tranzlatie



Mobilitatea se calculeaza cu formula lui Dobrovolsky


M=(G-f).n-S (n-f).Cn

Mecanizmul are patru cuple de clasa 5


M= 3n-C4-2C5 =9-0-2.4 =9-8 =1

M= 1



f=3


Mecanizmul este format din motoelementul OA si diada RRT


I= (0,15+0,05.8+0,01.1+0,035.42).0,7

I=(0,15+0,4+0,01+1,47).0,7


I=1,421


OA=I . 0,06=1,421.0,06


OA=0,08526 m


AB=I . 0,30=1,421.0,30


=0,4263 m AB


AC=I . 0,08=1,421.0,08


AC=0,11368 m


BC=I . 0,24=1,421.0,24


BC=0,34104


Q=I . 30=1,421.30


Q=42,63


w =I . 50=1,421.50


w


K=AB/[AB]=0,4263/100


K=0,004263[m/mm]


[AB]=100[mm]


[OA]=OA/Kl=0,08526/0,004263


[OA]=20[mm]


[AC]=AC/Kl=0,11368/0,004263=0,11368/0,004263


[AC]=26,6[mm]


[BC]=BC/Kl=0,34104/0,004263


[BC]=80[mm]


Viteze j


VA=OA . w


VA=6,057723m/s


KV=VA/[VA]=0,06057723 [m.s-1/mm]


VB/110x=VA+VBA/ AB


VB=ib.Kv=80.Kv


VB=4,8461784[m/s]


VBA=ab.Kv=73.Kv


VBA=4,42213779[m/s]


VBA=AB.w


w =VBA/AB


VBA=10,3733rad/s


DABC Dabc


AB/ab=BC/bc


BC/AB . ab


bc=0,34104/0,4263 . 73


AB/ab=58,4[mm]


AB/ab=AC/ac=AC/AB . ab


ac=0,11368/0,4263 . 73


ac=19,4[mm]


VC1=VA/2


VC1=3,0288615[m/s]


VC2=ic2.Kv=82.Kv


VC2=4,96733286[m/s]


VC=ic .Kv=82.Kv


VC=4,96733286[m/s]


Acceleratii j


aA=av.A+atA


aA=oA . w


aA=430,401219[m/s2]


Ka=aA/[aA]=430,401219/100


Ka=4,30401219[m/s2]


avBA=AB . w


avBA=45,872162[m/s2]



[avBA]=avBA/Ka=10,658[m/s2]


aB/110Y= aA+avBA/ AB+atBA/ AB

B A


atBA=m b . Ka


atBA=288,36817[m/s2]


atBA=AB.e


e =atBA/AB


e =676,445735[rad/s]


aB=jb . Ka=79 . Ka


aB=340,016963


DABC Da b c


AB/ab=AC/ac


ac=AC/AB . ab=0,11368/0,4263 . 70


ac=18,6[mm]


AB/ab=BC/bc


bc=BC/AB . ab=0,34104/0,4263 . 70


bc=56[mm]


ac=jc.Ka=100 . Ka


ac=430,401219[m/s2]


ac1=aA/2=215,200609[m/s2]

ac1=215,200609[m/s2]


ac2=jc2.Ka=90 . Ka


ac2=387,361097[m/s2]


Viteze j


VA=OA . w


VA=6,057723[m/s]


KV=0,06057723[m.s-1/mm]


VB=VA+VBA

oy   AB


VB=ib . KV=82 . KV


VB=4,96733286[m/s]


VBA=ab . KV=70 . KV


VBA=4,2404061[m/s]


VBA=AB . w


w =VBA/AB


w =9,947[rad/s]


DABC Dabc


AB/ab=AC/ac


ac=AC/AB . ab=0,11368/0,4263 . 70


ac=18,6[mm]


AB/ab.BC/bc


bc=BC/AB . ab=0,34104/0,4263


bc=56[mm]


VC1=3,0288615[m/s]


VC2=ic2.KV=92 . KV


VC2=5,57310516[m/s]


VC=ic.KV=103 . KV


VC=6,23945469[m/s]


Acceleratii j


aA=OA . w


aA=430,401219[m/s2]


Ka=aA/[aA]


Ka=4,30401219[m/s2


avBA=AB.w


avBA=42,1962828[m/s2]


[avBA]=avBA/Ka=9,80394128[m/s2]


aB= aA + aBA + atBA

oy   AB AB

B A


atBA=m b .Ka=70 . Ka


atBA=301,280853[m/s2]


atBA=AB.e


e =atBA/AB


e =706,734349[rad/s]


aB=j b . Ka=80 . Ka


aB=344,320975[m/s2]


DABC Da b c


AB/ab=AC/ac


ac=AC/AB . ab=0,11368/0,4263 . 73


ac=19,4[mm]


AB/ab=BC/bc


Bc=BC/AB . ab=0,34104/0,4263 . 73


bc=58,4[mm]


ac=jc . Ka=80 . Ka


ac=344,320975[m/s2]


ac1=aA/2

ac1=215.200609[m/s2]


ac2=jc2.ka.


ac2=80.ka


ac2=344,320975[m/s2]


Viteze  j


VA=OA.w


VA=6,057723[m/s]


KV=0,06057723[m.s-1/mm]


VB=VA+VBA


//oy AB


VB=ib.KV


VB=60.KV


VB=3,6346338[m/s]


VBA=AB.w


w =VBA/AB


w=8,526[rad/s]


DABC Dabc


AB/ab=AC/ac


ac=AC/AB.ab


ac=0,11368/0,4263.70


ac=18,6[mm]


AB/ab=BC/bc


Bc=BC/AB.ab


bc=0,34104/0,4263.70


bc=56[mm]


VC1=3,0288615[m/s]


VC2=ic2.KV=73.KV


VC2=4,42213779[m/s]


VC=ic.KV=80.KV


VC=4,8461784[m/s]



Acceleratii j


aA=430,401219[m/s2]


Ka=aA/[aA]


Ka=4,30401219[m/s2]


avBA=AB.w


avBA=30,9888878[m/s2]


[avBA]=avBA/Ka


[avBA]=7,20[m/s]


aB = aA + aBA + atBA

//oy //AB AB

B A


atBA=m b .Ka=69.Ka


atBA=296,976841[m/s2]


atBA=AB.e


e =atBA/AB


e =696,638144[m/s2]


aB=j .b .Ka=60.Ka


aB=258,240731[m/s2]


DABC Da b c


AB/ab=AC/ac


ac=AC/AB.ab=0,11368/0,4263.70


ac=18,6[mm]


AB/ab=BC/bc


bc=BC/AB.ab=0,34104/0,4263.70


bc=56[mm]


ac=jc .Ka=93.Ka


ac=400,273134[m/s2]


ac1=aA/2


ac1=215,200609[m/s2]


ac2=jc2.Ka=76.Ka


ac2=327,104926[m/s2]









Capitolul Nr.2


Metoda Analitica







l1=OA=0,08526


l2=AB=0,4263


AC=0,11368


BC=0,34104


w


OA .cosj +AB . cosj T l1cosj +l2cosj Tl2cosj =-l1cosj

l1 l2


OA.cosj +AB.sinj = S Tcosj =-l1cosj /l2 T

T S=0,08526 . sin450+0,4263.sin98,130=0,4821T

Ta =arc cos(-l1.cosj /l2) = arc cos(-0,08526.cos450/0,4263)


a


XA=-OA.w .cosj =-0,08526.71,05.cos450TXA=-4,2834m

YA=OA.w .sinj =0,08526 . 71,05 . sin450TYA=4,2834m


XA=OA.cosj =0,08526 . cos450TXA=0,06028m

YA=OA.sinj =0,08526 . sin450TYA=0,06028m


VA X2A+Y2A = 6,0577[m/s]


cosa=AB2+AC2-BC2/2AB.AC


cosa


cosa


a=arc cos 0,807651=84,43


-l2.sinj w -l1.sinj w

l2 . cosj w +l1.cosj w =s


w =l1.sinj /l2sinj w =0,08526.sin450/0,4263.sin82,12 . 71,05


w =10,1436rad


s=VB=l1.cosj w +l2.cosj w


s=0,08526.cos450.71,05+0,4263.cos82,120.10,1436


s=4,8461784[m/s]


-l2 .sinj w -l2 . sinj e =l1cosj w


-l2 . sinj w +l2 . cosj e =s+l1sinj w


e =l1.cosj w +l2.cosj w /l2.sinj


e =0,08526.cos450.71,05+0,4263.cos82,12.10,142/0,4263.sin82,120


e =674,4357[rad/s]


s= -l2sinj w +l2.cosj e -l1.sinj w


s=0,4263.sin82,12.10,142+0,08526.cos82,12.674,4357-0,08526.sin450.71,05


s=281,3688


XC=OA.cosj +AC.cos(j a


XC=0,08526.cos450+0,11368.(cos82,120-10,140)


XC=1,003[m/s]


YC=OA.sinj +AC.sin(j a


YC=0,08526.sin450+0,11368.sin(82,120-10,140)


YC=1,0039[m/s]


XC CX=-OA.w .cos450+AC.sina w =3,12084[m/s]


YC=OA.w .sin450+AC.cosa w =4,91741[m/s]


VC XC2+YC2=4,967312[m/s]





Capitolul Nr 3


Calculul fortelor si cuplurilor ce actioneaza pe elementul mecanizmului



Fi=-m.a-forta de inertie


Mi= - Kc-momentul fortelor de inertie



Fortele de greutate


OA=0,08526.mTdOA=OA/10=0,008526


mOA=jOL.V bara


jOL=7800Kg/m3


V bara=V cil=pd2/4.lOA=p.0,0085262/4 .0,08526=6,8.10-8m3


mOA=7800.6,8.10-8=0,000485Kg


V placi=A bazei.d placi


h placi=0,11368/10=0,011368m


Ab= p(p-a).(p-b).(p-c)


p=a+b+c/2=0,4269+0,11368+0,34104/2=0,44081m


Ab=


Ab=0,015129


V placi=0,015129.0,011368=2,612.10-6m3


m placa jOL.V placa=0,0212Kg


j


G1=m1.g=0,000485Kg.9,81=0,004757


G2=m2.g=0,0212 . 9,81=0,207972


ac1=215,2006[m/s2]


ac2=387,361[m/s2]


Fi1=-mOA.ac1=0,000485.215,2006=0,10437


Mi1=j1.e


e


I0=m.l21/3=4,2.10-8


Fi2=m2.ac2=0,0212.387,361=8,2120


Mi2=jc.e


Ic=m(l21+l22+l23)/36=9,817.10-6


j


G1=m1.g=0,004757


G2=m2.g=0,207972


ac1=215,2006[m/s2]


ac2=344,3209[m/s2]


Fi1=mOA.ac1=0,10437


Mi1=0=e .j0

w =ctTe


J0=m1.l12/3=4,2.10-8


Fi2=m2.ac2=8,2120


Mi2=jc.e


Jc=m2(l21+l22+l23)/36=9,718.10-6


j


G1=m1.g=0,004757


G2=m2.g=0,207972


ac1=215,2006[m/s2]


ac2=327,104[m/s2]


Fi1=mOA.ac1


Mi1=0=e .j0


w =ctTe


J0=ml1/3=4,2.10-8


Fi2=m2.ac2=8,2120


Mi2=jc.e


jc=m2(l21+l22+l23)/36=9,818.10-6



Capitolul Nr.4


Calculul reactiunilor din cuple



Calculul reactiunilor din cuple prin metoda grafo-analitica


SMB TN.X=0TX=0


SMA TMi2+Q.d5-Fi2.d7+G2.d2+Q.d6-N.d8=0


N=Mi2+Q.d5.KL-Fi2.d7.KL-G2.d2.KL+Q.d6.KL/d8.KL


N=0,5522+42,63.14.0,004263-8,2120.20.0,004263-0,2079.2.0,004263+42,63.23.0,004263/0,4263


N=10,31[N]


SMA TMi2+Q.d5-G2.d2-Fi2.d7-RtB.AB=0


RtB=Mi2+Q.d5.KL-G2.d2.KL-Fi2.d7.KL/AB


RtB=0,5522+42,63.14.0,004263-0,2079.2.0,004263.20.0,004263/0,4263


RtB=10,121[N]


SMB TFi2.d3+Mi2-Q.d4-G2.d9+RtA.AB=0


RtA=-Fi2.d3-Mi2+Q.d4.KL-G2.d9.KL/AB


RtA=8,2120-41-0,5522+42,63.76.0,004263-0,2079.12.0,004263/0,4263


RtA=9,21[N]


SF T RtB+N+Q+RnB=0


Kf=Q/[Q]=42,63/100=0,4263[N/mm]


[RtB]=Rtb/Kf=10,121/0,4263=23,7414[mm]

[N]=N/Kf=10,31/0,4263=24,1848[mm]


[RnB]=[RnB].Kf=96.0,4263=40,9248[N]


RB= Rn2B+Rt2B=9,1810[N]


SF T RtA+Fi2+G2+Q+Rna=0


[RtA]=RtA/Kf=9,21/0,4263=21,604


[Fi2]=Fi2/Kf=8,2120/0,4263=19,2634[mm]


Q=100[mm]


G2=G2/Kf=0,2079/0,4263=0,487684[mm]


RnA=[RnA].Kj=25.0,4263=106575[N]


SF TRA+Fi1+G1+R0=0


Fi1=Fi1/Kf=0,1043/0,4263=0,2446[mm]


G1=G1/Kf=0,00475/0,4263=0,011142[mm]


Ro=[Ro].Kf=98.0,4263=41,774


SMo TRa.d10+G1.d1-Mc1=0


Mc1=Ra.d10.KL+G1.d1.KL


Mc1=0,1816[N.m]



Capitolul Nr.5

Calculul reactiunilor din cuple













SMB T N.X=0 TX=0


SMA TN(XB-XA)-Q(XA-XB)-Fi2y(XA-XC2)+Fi2x(yC2-yA)-G2(XA-XC2)-Q(YC-YA)

N=Q(XA-XB)+Fi2y(XA-XC2)-Fi2x(YC2-YA)+G2(XA-XC2)+Q(YC-YA)/(XB-XA)


SFx TRBX+N=0TRBX=-N


SFy TRBY-Q=0TRBX=Q


SFx T-RBX-Fi2x-Q-RAX=0TRAX=Fi2x-RBX-Q


SFy T-RBY+Fi2Y-G2+RAY=0TRAY=RBY-Fi2+G2


SFX TROX+Fi1x+RAX=0TROX=-RAX-Fi1x


SFy TROY+Fi1Y+ROY=0TROY=-RAY-Fi1Y


SMo TMC1=G1(XC1-X0)+Fi1x(YC1-Y0)-Fi1Y(XC1-X0)+RAY(XA-X0)-RAX(YA-YO)


Momentul de inertie redus la elementul 1

J(red 1)


Jred 1=1/w S(j1.w +mi.vc2)


Jred=1/71,05(j1.w +j2.w +m2.VC22)


Jred=1/71,05(4,2.10-8.71,052+9,187.10-6.10,37332+0,0212.4,96732)=11,852.10-8Kg.m2



Momentul de inertie redus la elementul 1 Mred1


Mred=1/w S(Fj.Vj.cosaj+Mj.wj


Mred=1/w (Q.VL.cosa +Q.Vs.cosa +G1.VC1.cosa +G2.VC2.cosa


Mred1=1/71,05(42,63.4,9673.cos220+42,63+4,8461.cos180+0,004757.3,0288.cos2250+0,2079.4,9673.cos2100)

Mred1=0,873N.m

Cuprins :


Capitolul Nr 1 . . . . . . . . . . . . . . . . Pag.3

Analiza structurala . . . . . . . . . . . . . . Pag.3


Capitolul Nr.2 . . . . . . . . . . . . . . . . Pag.15

Metoda analitica . . . . . . . . . . . . . . . Pag.15


Capitolul Nr.3 . . . . . . . . . . . . . . . . Pag.18

Calculul fortelor si cuplurilor ce actioneaza pe elementul

mecanizmului . . . . . . . . . . . . . . . .Pag.18

3.1 Fortele de greutate . . . . . . . . . . . . ..Pag.18


Capitolul Nr.4 . . . . . . . . . . . . . . . .Pag.21

Calculul reactiunilor din cuple . . . . . . . . .Pag.21

4.1 Calculul reactiunilor din cuple prin metoda

grafo-analitica . . . . . . . . . . . . . . . . Pag.21


Capitolul Nr.5 . . . . . . . . . . . . . . . ..Pag.23

Calculul reactiunilor din cuple . . . . . . . . . ..Pag.23

5.1 Momentul de inertie redus la elementul 1 . . . ..Pag.24

5.2 Momentul de inertie redus la elementul 1 Mred1..Pag24.

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